5 October 2015

GATE Arch/Planning Question

Question : A housing project is proposed to be designed in a plot of 2 hectare. Maximum permissible FAR is 2. The share of the numbers of dwelling units (DU) for MIG, LIG and EWS is 1:2:3 having sizes of 55, 35 and 25 sq.m respectively. The maximum number of DU which can be accommodated in the plot is _______________

Answer: 1200
Soln: Since FAR is 2, maximum built up area for 2 ha plot will be 20,000 × 2= 40,000 m2  
Let there be ‘x’ MIG, ‘y’ LIG, and ‘z’ EWS no of dwelling units.
                       
55x +35y + 25z = 40,000 and x: y: z = 1: 2: 3

x/y= 1/2  and  y/z =    2/3   therefore

 x = y/2 and    z=  (3y)/2

(55 y )/2 + 35 y + 25 ( 3y)/2 = 40,000 solving this we get y = 400


Therefore MIG= 200, LIG= 400 and EWS = 600   ……………………..Total DU= 1200 

No comments:

Post a Comment