Question : A housing
project is proposed to be designed in a plot of 2 hectare. Maximum permissible
FAR is 2. The share of the numbers of dwelling units (DU) for MIG, LIG and EWS
is 1:2:3 having sizes of 55, 35 and 25 sq.m respectively. The maximum number of
DU which can be accommodated in the plot is _______________
Answer: 1200
Soln: Since FAR is 2, maximum built up area
for 2 ha plot will be 20,000 × 2= 40,000 m2
Let there be ‘x’ MIG, ‘y’ LIG, and ‘z’ EWS
no of dwelling units.
55x +35y + 25z = 40,000 and x: y: z = 1: 2: 3
x = y/2 and
z=
(3y)/2
(55 y )/2 + 35 y + 25 (
3y)/2 = 40,000 solving this we get y = 400
Therefore MIG= 200, LIG= 400 and EWS = 600 ……………………..Total DU= 1200
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